Posted on December 1, 2009 by Chad Salinas
Counterexample:
Γ = {}
φ = p(x)
ψ = ∀x p(x)
Now, applying Deduction Theorem, from prop. logic, substituting above Γ |= (φ ⇒ ψ) iff Γ ∪ {φ} |= ψ yields:
({} |= (p(x) ⇒ ∀x p(x)) ⇔ ({p(x)} |= ∀x p(x))
The LHS of this equivalence is the logical entailment {} |= (p(x) ⇒ ∀x p(x). For this entailment to be true we need the logical sentence p(x) ⇒ ∀x p(x) to be valid in relational logic, but we have shown that p(x) ⇒ ∀x p(x) is contingent. Therefore the entailment is false.
On RHS, we have the entailment {p(x)} |= ∀x p(x). Consider the following short proof:
1 p(x) Premise
2 ∀x p(x) UG
Thus {p(x)} |- ∀x p(x) and, by soundness, {p(x)} |= ∀x p(x). So the right-hand entailment is true.
Since assuming the Deduction Theorem for prop. Logic holds for relational logic leads to the contradictory equivalence F ⇔ T, our assumption must be false; i.e. DT does not hold.
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Posted on December 1, 2009 by Chad Salinas
Deduction Theorem:
Δ |- (φ ⇒ ψ) if and only if
Δ∪{φ} |- ψ.
Substitution Theorem:
Δ |- (φ ⇔ ψ) and Δ |- χ, then it
is the case that Δ |- χφ←ψ.
ChainingTheorem:
If Δ|-(φ⇒ψ)andΔ|-(ψ⇒χ), then Δ |- (φ ⇒ χ).
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Posted on October 12, 2009 by Chad Salinas
There is a close connection between provability and logical entailment. In fact, they are equivalent. A set of sentences Δ logically entails a sentence φ if and only if φ is provable from Δ.
Soundness Theorem: If φ is provable from Δ, then Δ logically entails φ.
Completeness Theorem: If Δ logically entails φ, then φ is provable from Δ.
The concept of provability is important because it suggests how we can automate the determination of logical entailment. Starting from a set of premises Δ, we enumerate conclusions from this set. If a sentence φ appears, then it is provable from Δ and is, therefore, a logical consequence. If the negation of φ appears, then ¬φ is a logical consequence of Δ and φ is not logically entailed (unless Δ is inconsistent). Note that it is possible that neither φ nor ¬φ will appear.
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Posted on October 11, 2009 by Chad Salinas
Standard Axiom Schemata for Propositional Logic
(II): φ ⇒ (ψ ⇒ φ)
(ID): (φ ⇒ (ψ ⇒ χ)) ⇒ ((φ ⇒ ψ) ⇒ (φ ⇒ χ))
(CR): (¬φ ⇒ ψ) ⇒ ((¬φ ⇒ ¬ψ) ⇒ φ)
(EQ):
(φ ⇔ ψ) ⇒ (φ ⇒ ψ)
(φ ⇔ ψ) ⇒ (ψ ⇒ φ)
(φ ⇒ ψ) ⇒ ((ψ ⇒ φ) ⇒ (φ ⇔ ψ))
(OQ):
(φ ⇐ ψ) ⇔ (ψ ⇒ φ)
(φ ∨ ψ) ⇔ (¬φ ⇒ ψ)
(φ ∧ ψ) ⇔ ¬(¬φ ∨ ¬ψ)
(II), (ID), and (CR) form the Mendelson Axiom Schemata for Propositional Logic
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